MEMMOVE
Section: Linux Programmer's Manual (3)
Updated: 1993-04-10
NAME
memmove - copy memory area
SYNOPSIS
#include <string.h>
void *memmove(void *dest, const void *src, size_t n);
DESCRIPTION
The
memmove()
function copies n bytes from memory area
src to memory area dest.
The memory areas may overlap: copying takes place as though
the bytes in
src
are first copied into a temporary array that does not overlap
src
or
dest,
and the bytes are then copied from the temporary array to
dest.
RETURN VALUE
The
memmove()
function returns a pointer to dest.
CONFORMING TO
SVr4, 4.3BSD, C89, C99, POSIX.1-2001.
SEE ALSO
bcopy(3),
memccpy(3),
memcpy(3),
strcpy(3),
strncpy(3),
wmemmove(3)
COLOPHON
This page is part of release 3.27 of the Linux
man-pages
project.
A description of the project,
and information about reporting bugs,
can be found at
http://www.kernel.org/doc/man-pages/.
Index
- NAME
-
- SYNOPSIS
-
- DESCRIPTION
-
- RETURN VALUE
-
- CONFORMING TO
-
- SEE ALSO
-
- COLOPHON
-
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Time: 07:35:25 GMT, March 26, 2013